timer & overflow interrupt MikroC code

Question

void TimerFunction()
{
TIMSK=(1<<TOIE0);
TCNT0=0x00;
TCCR0 |= (0<<CS02) | (1<<CS00) | (0<<CS01);
}

//##############################################################################
ISR(TIMER0_OVF_vect)
{
    // process the timer0 overflow here
  countClock ++;
  count++;
  delay++;
//some extra code 
}

then

void main()
{
 //someCode
 TimerFunction();
}

but it doesnt work for me ,so is that the right way to start the timer 0 and its interrupt service routine ??

MikeD · Answer 1 · 2013-08-02T16:47:57.263

0

At first sight I'd say you miss

sei();  // set global interrupt flag

if this is not within //someCode ... in any case I recommend turning on the global interrupt enable flag only after initializing all specific interrupt sources (timers, USART, etc)

edited Aug 02 '13 at 16:47

answered Aug 02 '13 at 15:39

MikeD

8,861
2
28
50

undeclared indentifier "sei" expression – Ahmed Zain El Dein Aug 02 '13 at 15:53
`sei()` is normally defined in `` ... have you `#include` d that? – MikeD Aug 02 '13 at 16:32
i use Mikro C for avr compiler as i know there is no #include in it – Ahmed Zain El Dein Aug 02 '13 at 16:33
then try to use `SREG_I = 1;` – MikeD Aug 02 '13 at 16:43
maybe SREG_I is the position of the bit within the SREG ... sorry I am not familiar with MikroC - using AVR Studio ... anyway - you need to set the global interrupt enable bit which is bit 7 of the AVR status register – MikeD Aug 02 '13 at 16:55

score 0 · Answer 2 · answered Oct 23 '13 at 08:28

0

Yes, in your code global interrupt flag is not set. If solutions which purposed MikeD are not working, try this:

asm{sei};

answered Oct 23 '13 at 08:28

Dmitry

1

score 0 · Answer 3 · answered Oct 06 '15 at 17:16

0

use SREG.SREG_I = 1; to enable global interrupts

answered Oct 06 '15 at 17:16

Soheil Paper

1
2
8
25

timer & overflow interrupt MikroC code

3 Answers3