How can I use line.replace to add space around any brackets in a string that are elements in another bracket set, through a loop?

Question

brackets = {')', '(', '{', '}', '[', '>', ']', '<'}

string_line = <[2{12.5 6.0}](3 -4 5)>'

Basically I have to add space around any brackets in a string_line for brackets that are in the set. e.g. '[' becomes ' [ ' Assuming that I wouldn't know what brackets it contains, how can i avoid repeating line.replace 8 times? (there are 8 types of brackets)

Thanks!

Hyperboreus · Accepted Answer · 2013-08-04T07:39:27.937

You could try using regular expressions. The stupid while loop at the end is due to fact that I do not know how to replace overlapping matches. I would be grateful for any advice on this item.

#! /usr/bin/python3

import re

string_line = '<[2{12.5 6.0}](3 -4 5)>'

while True:
    string_line, count = re.subn ('[{}<>\[\]()][{}<>\[\]()]', lambda x: '{} {}'.format (*x.group () ), string_line)
    if not count: break

print (string_line)

This yields:

< [2{12.5 6.0} ] (3 -4 5) >

Basically inserting a whitespace between two following brackets. If this is not the expected behaviour please let me know the expected output.

Z3r0n3 · Answer 2 · 2013-08-04T08:33:05.143

0

try with list operations:

import functools
def replaceif(x):
    if x in brackets:
        x=' '+x+' '
    return x
brackets = [')', '(', '{', '}', '[', '>', ']', '<']
string_line = '<[2{12.5 6.0}](3 -4 5)>'
print(functools.reduce(lambda x,y: replaceif(x)+replaceif(y), string_line))

edited Aug 04 '13 at 08:33

answered Aug 02 '13 at 07:36

Z3r0n3

37
4

This produces `[')', '(', '{', '}', ' [ ', '>', ']', '<']`. – Hyperboreus Aug 02 '13 at 17:58
Why don't you just write `[' '+x+' ' for x in brackets]`? This does the same as your code and is also completely unrelated to the question. – Hyperboreus Aug 03 '13 at 21:52

How can I use line.replace to add space around any brackets in a string that are elements in another bracket set, through a loop?

2 Answers2