How to modify a result in calculation?

Question

Formula is (val x 0.5) + 50 = result, but if result is greater then 200, then override result to 150

My if is if (val > 200) { result = 150 }

What are you looking for help with? – Avitus Jul 31 '13 at 00:38 — Avitus, Jul 31 '13 at 00:38
@bfavaretto it works too well – aaronman Jul 31 '13 at 00:38 — aaronman, Jul 31 '13 at 00:38
So.... what is the question? – AlienHoboken Jul 31 '13 at 00:56 — AlienHoboken, Jul 31 '13 at 00:56

Avitus · Accepted Answer · 2013-07-31T00:46:29.990

0

If you just need a function:

function doSomething(val)
 {
   var result = val *.5 + 50;

   if ( result > 200 )
 {
    result = 150;
  }

return result;
}

In one line I suppose it would be:

var result = (val*.5) + 50 > 200 ? 150 : (val*.5) + 50;

edited Jul 31 '13 at 00:46

answered Jul 31 '13 at 00:40

Avitus

score 0 · Answer 2 · answered Jul 31 '13 at 00:44

0

I'm assuming if val<= 200, the result will be the real result.

    var result = (val * 0.5) +50;

    result = result>200?150:result;

answered Jul 31 '13 at 00:44

CalebC

2 Answers2