C windows sendto()

Question

I am trying to send over UDP using the following code, but i'm getting strange results.

    if((sendto(newSocket, sendBuf, totalLength, 0, (SOCKADDR *)&sendAddr, sizeof(sendAddr)) == bytesSent) < 0)
    {
    printf("Send error! - %d\n", WSAGetLastError());

    }

However say when the totalLength variable is set to 30 the sendto function actually returns 2292556, should it not be returning something at least around the 30 mark? I have checked the totalLength variable before using sendto and it will happily return a value i agree with, but then sendto returns a massive value. Total length is never bigger then the actual buffer size.

WSAGetLastError is just returning 0.

Thanks.

score 1 · Accepted Answer · answered Nov 23 '09 at 21:03

1

I think your problem is the == bytesSent) < 0) part of the conditional. Should'n this be something along the lines of if (( bytesSent = sendto( ... )) < 0 )?

answered Nov 23 '09 at 21:03

Nikolai Fetissov

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Ah yes of course I cant believe I didn't see that. I've been frustrated by this for nearly an hours v.v – Alistair Nov 23 '09 at 21:05
Blame =, == and lines that are too long :) – schnaader Nov 23 '09 at 21:06

score 0 · Answer 2 · answered Mar 24 '12 at 09:33

0

You are checing if sendto(...) is equal to bytesSent instead of probably bytesSent=sendto

answered Mar 24 '12 at 09:33

C windows sendto()

2 Answers2