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@echo off
set START_SERVER="C:\Program Files\Apache\Tomcat_6\bin\startup.bat"
call %START_SERVER%
start http://localhost:8080/MyProject/

  • How to launch app in browser after server start using batch?

  • My above script is starting server and launching app.. but both working simultaneously.

  • I want to launch app after server startup is done
Bobby Rachel
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2 Answers2

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your code is right. The startwill run, when startup.bat is finished. The problem propably is in startup.bat Propably it starts an exe-file, and then exits, before that exefile is fully started. You can edit startup.bat or set an timeoutbetween the callline and the startline.

Stephan
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Not sure if it will help any one but one can use timeout something like below:

@echo off set START_SERVER="C:\Program Files\Apache\Tomcat_6\bin\startup.bat" call %START_SERVER% echo "Waiting 1 minutes for the application to start" timeout /T 60 start http://localhost:8080/MyProject/

Arpit Tripathi
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