regex for url in image tag with unknown part in the middle using PHP

Question

Here are the ingredients:

html text
oldpath, e.g. /assets/uploads/
newpath, e.g. /assets/newFolder/
oldfilename, e.g. oldImage.jpg
newfilename, e.g. newImage.jpg

in the html there are images like this:

<img src="[oldpath]xxx[oldfilename]" />

What I want to do is write a regex that can replace instances of this with a new file name and path using PHP and/or MYSQL (prefer PHP) so that it becomes:

 <img src="[newpath]xxx[newfilename]" />

xxx are a bunch of characters, e.g. /_resampled/croppedimage170170-, but I dont know the exact content of xxx.

So i want to end up with something like

<?php
$newHtml = preg_replace(MAGIC GOES HERE);

Thank you in advance.

Nicolaas

`your_src.replace(oldfilename, newfilename)`. Please be more descriptive. — mishik, Jul 23 '13 at 08:20
See [How do you parse and process HTML/XML in PHP?](http://stackoverflow.com/q/3577641) — Pekka, Jul 23 '13 at 08:20
I dont think that this is really going to do the trick. Looks more like JS. — nicolaas thiemen francken, Jul 23 '13 at 08:26
@DarkBee, I have the new filename. I could do a straight str_replace(old, new, html), but the xxx part in the middle makes it a little harder. I dont know the xxx part in the middle and I dont want to replace the path and the filename independently as this might replace too many instances. — nicolaas thiemen francken, Jul 23 '13 at 08:47

keyneom · Answer 1 · 2013-07-23T08:46:45.367

1

The regex should be /oldPath(.*?)old filename/ and the replacement would be newPath$1newFilename. I.e.

preg_replace('/oldpath(.*?)oldfilename/', 'newpath$1newfilename', originalHTMLstring);

edited Jul 23 '13 at 08:46

answered Jul 23 '13 at 08:37

keyneom

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regex for url in image tag with unknown part in the middle using PHP

1 Answers1