Cannot deserialize the current JSON array (e.g. [1,2,3]) into type

Question

I have a class like this:

public class MyStok
{
    public int STId { get; set; }
    public int SM { get; set; }
    public string CA { get; set; }
    public string Br { get; set; }
    public string BNo { get; set; }
    public decimal Vat { get; set; }
    public decimal Price { get; set; }
}

I deserialize like this:

string sc = e.ExtraParams["sc"].ToString();
MyStok myobj = JSON.Deserialize<MyStok>(sc);

My output seems to be like this (string sc) on fiddler:

[
    {
        "STId": 2,
        "CA": "hbh",
        "Br": "jhnj",
        "SM": 20,
        "Vat": 10,
        "Price": 566,
        "BNo": "1545545"
    }
]

But I get the error:

Cannot deserialize the current JSON array (e.g. [1,2,3]) into type [...]

What is wrong in that code?

score 110 · Accepted Answer · answered Jul 20 '13 at 12:01

It looks like the string contains an array with a single MyStok object in it. If you remove square brackets from both ends of the input, you should be able to deserialize the data as a single object:

MyStok myobj = JSON.Deserialize<MyStok>(sc.Substring(1, sc.Length-2));

You could also deserialize the array into a list of MyStok objects, and take the object at index zero.

var myobjList = JSON.Deserialize<List<MyStok>>(sc);
var myObj = myobjList[0];

score 28 · Answer 2 · edited Jul 22 '21 at 07:44

28

For array type Please try this one.

 List<MyStok> myDeserializedObjList = (List<MyStok>)Newtonsoft.Json.JsonConvert.DeserializeObject(sc, typeof(List<MyStok>));

Please See here for details to deserialise Json

edited Jul 22 '21 at 07:44

Mark Rotteveel

100,966
191
140
197

answered Jul 20 '13 at 12:07

Janty

1,708
2
15
29

Thank you so much for the example, you saved my day... I was missing the point of using a List Of. – Marçal Torroella Mar 02 '22 at 17:00
This approach is really perfect....Thanks!! – MD. RAKIB HASAN Apr 07 '22 at 07:23

score 2 · Answer 3 · answered Aug 23 '21 at 11:04

2

Another alternative if you have a root level array with no name and you actually want to use it for something, like adding methods

public class MyStoks : List<MyStok> 
{

}

Then you can deserialize like this

MyStoks myObj = JsonConvert.DeserializeObject<MyStoks>(jsonString);

answered Aug 23 '21 at 11:04

John

192
3
12

This was a more elegant solution to me. You do not have to deserialize it as a list, as the list is built into the JSON object class. – Bullfrog Software Oct 26 '22 at 13:13

score 1 · Answer 4 · answered Feb 24 '21 at 17:57

I ran into this exact same error message. I tried Aditi's example, and then I realized what the real issue was. (Because I had another apiEndpoint making a similar call that worked fine.) In this case The object in my list had not had an interface extracted from it yet. So because I apparently missed a step, when it went to do the bind to the

List<OfthisModelType>

It failed to deserialize.

If you see this issue, check to see if that could be the issue.

score -1 · Answer 5 · answered Apr 25 '17 at 09:43

-1

HttpClient webClient = new HttpClient();
Uri uri = new Uri("your url");
HttpResponseMessage response = await webClient.GetAsync(uri)
var jsonString = await response.Content.ReadAsStringAsync();
var objData = JsonConvert.DeserializeObject<List<CategoryModel>>(jsonString);

answered Apr 25 '17 at 09:43

Aditi_Systematix

105
2
5

This doesn't really add any value to the question or the other answers. – infl3x Apr 25 '17 at 10:26
this will apply only if you have HttpClient Call I marked as the answer is useful Cause the last line has the answer which is Deserialize it as a list of the class JsonConvert.DeserializeObject>(jsonString); – khaled Dehia Jul 03 '17 at 17:00
Thank you for this code snippet, which might provide some limited, immediate help. A [proper explanation](https://meta.stackexchange.com/q/114762/349538) would greatly improve its long-term value by showing why this is a good solution to the problem and would make it more useful to future readers with other, similar questions. Please [edit] your answer to add some explanation, including the assumptions you’ve made. – jasie Mar 02 '21 at 09:37

Cannot deserialize the current JSON array (e.g. [1,2,3]) into type

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