How to write Regex for input values?

Question

What RegEx can I use to parse a string so that it accepts only integers and the / character?

You should have tried something before asking a *quick reply*. — sp00m, Jul 16 '13 at 10:05
What have you tried already? StackOverflow is here to help you, not write your code for you. — Adrian Wragg, Jul 16 '13 at 10:05
A previous post partially solves your problem hope it helps http://stackoverflow.com/questions/9043551/regex-match-integer-only — AurA, Jul 16 '13 at 10:07

eyecatchUp · Accepted Answer · 2013-07-16T10:23:07.993

2

var a = '123/4';
var b = 'e123/4';

Variant 1

var regex = new RegExp('^[0-9/]+$');

console.log((a.match(regex)) ? true : false); // true
console.log((b.match(regex)) ? true : false); // false

Variant 2

var regex = /^[0-9/]+$/;

console.log((a.match(regex)) ? true : false); // true
console.log((b.match(regex)) ? true : false); // false

Variant 3

var regex = /^[\d\/]+$/;

console.log((a.match(regex)) ? true : false); // true
console.log((b.match(regex)) ? true : false); // false

edited Jul 16 '13 at 10:23

answered Jul 16 '13 at 10:09

eyecatchUp

why not `var regex = /^[0-9/]+$/;`? – Martin Ender Jul 16 '13 at 10:11
I'm just used to write it that way. Shouldn't be a difference though, right? – eyecatchUp Jul 16 '13 at 10:13
Btw, you could also write the regex as `/^[\d\/]+$/`. – eyecatchUp Jul 16 '13 at 10:18
1

I think using the constructor should be slightly less efficient, because you need to create a string object and have the overhead of another function call. Plus, the syntax gets a lot more ugly, when you use escapes (because you need to double all backslashes). I'd only use the constructor for dynamically created (concatenated) patterns. – Martin Ender Jul 16 '13 at 10:27

1 Answers1