Get $_FILES temp name (of the binary file)

Question

i'm in trouble this is an example of $_FILES['file']['tmp_name']

/Applications/XAMPP/xamppfiles/temp/phpjCag18

i would like to get the temp binary filename so in this case phpjCag18

Is there anyway to get it from the $_FILES[]?

Ho to get it clean from path ?

basename() or explode() on slashes and use the last element of the result. — GordonM, Jul 15 '13 at 09:40

score 4 · Answer 1 · answered Jul 15 '13 at 09:42

4

You can use basename() for this purpose.

$tmp = $_FILES['file']['tmp_name'];
echo basename( $tmp );

Or, if you're trying to get the extension, use pathinfo():

$extension =  strtolower( pathinfo($_FILES['file']['tmp_name'], PATHINFO_EXTENSION) );

answered Jul 15 '13 at 09:42

Amal Murali

thanks just accepted the other's answer cause he was just faster :P thanks a lot for explanation +1 – itsme Jul 15 '13 at 10:40

score 2 · Accepted Answer · answered Jul 15 '13 at 09:39

2

If I understand you correctly:

basename($_FILES['file']['tmp_name'])

answered Jul 15 '13 at 09:39

rr-

right , gonna accept your answer since returns exatcly what i need – itsme Jul 15 '13 at 09:41

2 Answers2