PHP: LOCAL_LOG0 isn't recognized

Asked Jul 07 '13 at 21:16

Active Jul 07 '13 at 21:26

Viewed 114 times

I am working on Ubuntu (it use rsyslog), and I need to custom log some info with PHP. Here is my code:

openlog("mywebsite", LOG_PID | LOG_PERROR, LOG_LOCAL2);
syslog(LOG_WARNING, "mywebsite: 1000th visitor !");
closelog();

and I defined in /etc/rsyslog/rsyslog.d/50-default.conf :

local2.* /var/log/apache2/mywebsite.log

the file mywebsite is defined chmod 777 but nothing appears in mywebsite.log but still in error.log

I found out that it's because PHP doesn't recognize LOG_LOCAL2 or LOG_LOCAL0, in

openlog("mywebsite", LOG_PID | LOG_PERROR, LOG_LOCAL2);

I catch the error:

PHP Notice: Undefined variable: access in /var/www/default/public_html/index.php on line 6

despite it's defined in the offcial documentation: PHP Official manual for openlog()

PS: I am on PHP 5.3.10

How can I resolve this?

edited Jul 07 '13 at 21:26

asked Jul 07 '13 at 21:16

Pierre Lebon

The error is about some `$access` variable yet I don't see it anywhere in your code. – PeeHaa Jul 07 '13 at 21:21
it's my full code exept the `` – Pierre Lebon Jul 07 '13 at 21:26
1

If that is your full code how can PHP complain about line6? – PeeHaa Jul 07 '13 at 21:27
I'm happy to learn that and text use PHP. – Pierre Lebon Jul 07 '13 at 21:56
I'm happy to learn that `` makes up a valid html document – PeeHaa Jul 07 '13 at 22:00
2

@PeeHaa Actually you need a DOCTYPE and a title and a bunch of other stuff. Pierre you'll probably have better luck in askubuntu. – Benjamin Gruenbaum Jul 07 '13 at 22:01
Thanks i didn't know askubuntu. Have a nice day – Pierre Lebon Jul 07 '13 at 22:03

0 Answers0