Python - Searcing MixedCase with regex

Question

I wonder if someone could help me solving this problem, I've tried this 2 regex but no success. I wonder if I'm doing wrong anywhere in the expression?

string[1] = "MixEdCasE"
string[2] = "MiXeD CaSE"    
re.search("^(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])[a-zA-Z0-9]{8}$", string[num])
re.search(r'(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])[a-zA-Z0-9]{8}$', string[num])

@AmineHajyoussef just trying to built a moderator function with regex — Natsume, Jul 04 '13 at 02:22
@Jack You know what, I didn't thought of that. Aiyayaya I'm always making things complicated -__- . Thank you anyway — Natsume, Jul 04 '13 at 04:08

score 0 · Answer 1 · answered Jul 04 '13 at 02:23

0

This pattern works well:

re.search(r'^(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])[a-zA-Z0-9]{8}$', string[num])

The problem is that your example strings contain more than 8 characters.

answered Jul 04 '13 at 02:23

Casimir et Hippolyte

88,009
5
94
125

Tried to increased it, but still no luck – Natsume Jul 04 '13 at 02:40
@Natsume: with this pattern you must have exactly 8 characters. to allow more replace `{8}` by `{8,}` – Casimir et Hippolyte Jul 04 '13 at 03:22
still no luck either. `>>> re.search(r'^(?=.*[a-z])(?=.*[A-Z])(?=.*[0-9])[a-zA-Z0-9]{8,}$', "MixEdCasE") >>> ` – Natsume Jul 04 '13 at 03:35
@Natsume: `MixEdCasE` doesn't contain digits. – Casimir et Hippolyte Jul 04 '13 at 21:50

Python - Searcing MixedCase with regex

1 Answers1