you can sort by using fields
consider an Example :
If you have 5 FACETS and COUNT associated with it.
Then you can sort by using the COUNTS of each fields.
It can be applicable to normal/non-facets fields .
public class FacetBean implements Category,Serializable {
private String facetName; //getter , setters
private long facetCount; // getter , setters
public FacetBean(String facetName, long count,) {
this.facetName = facetName;
this.count = count;
}}
Your calling method should be like this
private List<FacetBean> getFacetFieldsbyCount(QueryResponse queryResponse)
{
List<FacetField> flds = queryResponse.getFacetFields();
List<FacetBean> facetList = new ArrayList<FacetBean>();
FacetBean facet = null;
if (flds != null) {
for (FacetField fld : flds) {
facet = new FacetBean();
facet.setFacetName(fld.getName());
List<Count> counts = fld.getValues();
if (counts != null) {
for (Count count : counts) {
facet.setFacetCount(count.getCount());
}
}
facetList.add(facet);
}
}
Collections.sort(facetList,new Comparator<FacetBean>() {
public int compare(FacetBean obj1, FacetBean obj2) {
if(obj1.getFacetCount() > obj2.getFacetCount()) {
return (int)obj1.getFacetCount();
} else {
return (int)obj2.getFacetCount();
}
}
});
return facetList;
}
In The same URL They have mentioned something like.
sort -- >ex : For example, sort=popularity desc will cause the groups to be sorted according to the highest popularity doc
group.sort -- > you can apply your field here .
Hope it helps.