Variable variables created within a for loop

Question

I'd like to change this:

if ($week_day == "1")
{
$day1_hours = $value;
}
if ($week_day == "2")
{
$day2_hours = $value;
}
if ($week_day == "3")
{
$day3_hours = $value;
}
if ($week_day == "4")
{
$day4_hours = $value;
}
if ($week_day == "5")
{
$day5_hours = $value;
}
if ($week_day == "6")
{
$day6_hours = $value;
}
if ($week_day == "7")
{
$day7_hours = $value;
}
}

Into something more readable, like a for loop, or whatever other suggestions you all may have.

I tried to do:

for ($c=1; $c<8, $c++)
{
if ($week_day == $c)
{
$day".$c."_hours = $value;
}
}

But I know that is nowhere near correct, and I have no idea how to insert another variable within a variable.

Any help is appreciated!

Wouldn't it be easier to set an array key? `$day[$week_day] = $value` — andrewsi, Jul 03 '13 at 00:50
Check manual for more info http://php.net/manual/en/language.types.array.php. Please try your own code. Posting invalid syntax doesn't show an attempt at solving the problem... — elclanrs, Jul 03 '13 at 00:52
Could you post the full code for this situation as an answer? Declaring the array and so on? — RobDubya, Jul 03 '13 at 00:52
@RobDubya - it's literally one extra line, the where you declare the array. You'll end up with an array where the key is the $week_day value, and the value is whatever's in $value. — andrewsi, Jul 03 '13 at 00:55
I also need the _hours portion of the variable for stuff further along in the code, will it keep that, so would $day[$week_day]_hours = $value work? — RobDubya, Jul 03 '13 at 01:00
You can replace it with `$day[$week_day]` - that's what you're setting value to — andrewsi, Jul 03 '13 at 01:12

score 1 · Accepted Answer · answered Jul 03 '13 at 00:52

1

Try this syntax.

${'day'.$c.'_hours'} = $value;

answered Jul 03 '13 at 00:52

sectus

15,605
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No joy, loads a blank page. – RobDubya Jul 03 '13 at 00:57

score 0 · Answer 2 · answered Jul 03 '13 at 00:56

0

Try this

$hours[$week_day] = $value

answered Jul 03 '13 at 00:56

Kris

6,094
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score 0 · Answer 3 · answered Jul 03 '13 at 01:04

0

Something like this

$week_day = 3;
$value = "hi";

${"day" . $week_day . "_hours"} = $value;  

echo $day3_hours;

answered Jul 03 '13 at 01:04

Lloyd Banks

35,740
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score 0 · Answer 4 · answered Jul 03 '13 at 01:17

0

My interpretation.

$week = 7;
$day = array();

for($i=1; $i<=7; $i++){
   $day[$i]['hours'] = $value;
}

You can declare the numbers of weeks you want and to pull the data you can do something like this:

echo $day[1]['hours']

answered Jul 03 '13 at 01:17

Drixson Oseña

3,631
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Variable variables created within a for loop

4 Answers4