Java (ZipEntry) - if the file name contains czech characters (čžř etc) it fails while reading next entry

Question

I have a problem when I try to unzip file contains files with special characters.

Lets say I have a zip file gallery.zip with image files.

gallery.zip
  - file01.jpg
  - dařbuján.jpg

My method starts:

public List<File> unzipToTemporaryFolder(ZipInputStream inputStream)
        throws IOException {
    List<File> files = new LinkedList<File>();
    ZipEntry entry = null;
    int count;
    byte[] buffer = new byte[BUFFER];

    while ((entry = inputStream.getNextEntry()) != null) {

It fails in inputStream.getNextEntry() when I try to read file dařbuján.jpg because of czech letters "ř" and "á". It works well with the other files for example with spaces (104 25.jpg or simply file.jpg etc.). Can you help me please?

Yes, in the meantime I've googled your problem. It's easy to find. — Marko Topolnik, Jul 02 '13 at 12:02
Then I presume you're not on Java 7. For earlier versions you are out of luck. Did you read [this](http://bugs.sun.com/view_bug.do?bug_id=4244499) bug report? — Marko Topolnik, Jul 02 '13 at 13:04
A few more explanation on bug 4244499 (mentionned by @MarkoTopolnik) : https://blogs.oracle.com/xuemingshen/entry/non_utf_8_encoding_in — potame, Aug 25 '15 at 12:50

score 2 · Answer 1 · answered Jul 02 '13 at 11:42

2

Create your ZipInputStream with Charset specified using

 ZipInputStream(InputStream in, Charset charset)

like

new ZipInputStream(inputStream, Charset.forName("UTF-8"));

answered Jul 02 '13 at 11:42

Ravi K Thapliyal

51,095
9
76
89

Well there is a problem that ZipInputStream accepts only one parameter... InputStream in. No charset. – Jan Bouchner Jul 02 '13 at 11:50
Oh I see. This is Java 7 thing. – Jan Bouchner Jul 02 '13 at 12:02

score 1 · Accepted Answer · answered Jul 02 '13 at 15:27

Ok, I solved it with commons-compress. If somebody is interested here is my method:

public List<File> unzipToTemporaryFolder(ZipInputStream inputStream,
        File tempFile) throws IOException {
    List<File> files = new LinkedList<File>();
    int count;
    byte[] buffer = new byte[BUFFER];

    org.apache.commons.compress.archivers.zip.ZipFile zf = new org.apache.commons.compress.archivers.zip.ZipFile(tempFile, "UTF-8");
    Enumeration<?> entires = zf.getEntries();
    while(entires.hasMoreElements()) {
        org.apache.commons.compress.archivers.zip.ZipArchiveEntry entry = (org.apache.commons.compress.archivers.zip.ZipArchiveEntry)entires.nextElement();
        if(entry.isDirectory()) {
            unzipDirectoryZipEntry(files, entry);
        } else {            
            InputStream zin = zf.getInputStream(entry);                 

            File temp = File.createTempFile(entry.getName().substring(0, entry.getName().length() - 4) + "-", "." + entry.getName().substring(entry.getName().length() - 3, entry.getName().length()));                                     

            OutputStream outputStream = new BufferedOutputStream(new FileOutputStream(temp), BUFFER);
            while ((count = zin.read(buffer, 0, BUFFER)) != -1) {
                outputStream.write(buffer, 0, count);
            }
            outputStream.flush();
            zin.close();
            outputStream.close();
            files.add(temp);            
        }
    }
    zf.close();
    return files;
}

Java (ZipEntry) - if the file name contains czech characters (čžř etc) it fails while reading next entry

2 Answers2