php code becomes xml?

Question

I'm trying to evaluate the contents of mapvar.php and saving it to a variable. This is the code:

<?php
$filename = strval(rand(0,99999999999)).'.svg';
$fp=fopen($filename, 'wb+');

ob_start();
include 'mapvar.php';
$output = ob_get_clean();
ob_flush();

file_put_contents($filename,$output);
?>

<form action="download.php" method="post">
    <input type="hidden" name="filename" value="<?php echo $filename ?>" />
    <input type="submit" value="dl" />
</form>
<?php fclose($fp); ?>

For some reason, when I open the file, this message shows up (in both Chrome and FF):

"This XML file does not appear to have any style information associated with it. The document tree is shown below."

...and then the evaluated html code.

It seems to be caused by the ob_start() stuff, why is this?

how does your mapvar.php look like? – Software Guy Jun 30 '13 at 15:18 — Software Guy, Jun 30 '13 at 15:18
It's an svg image with php variables. Solved anyway. – chintogtokh Jun 30 '13 at 15:52 — chintogtokh, Jun 30 '13 at 15:52

score 1 · Accepted Answer · answered Jun 30 '13 at 15:14

1

mapvar.php probably sends a Content-Type: image/svg+xml header or something like that. You can override it later:

$output = ob_get_clean();
ob_flush();
header('Content-Type: text/html');

Also, there’s no need to use fopen or fclose with file_put_contents.

answered Jun 30 '13 at 15:14

Ry-

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Ah that was it, I modified the header at mapvar.php, I can't change the header like yours (Cannot modify header information - headers already sent). Thanks. – chintogtokh Jun 30 '13 at 15:52

php code becomes xml?

1 Answers1