Define function with more than 1 prototype

Question

I am working on a function that I would like to define more than one prototype and was wondering if this is possible.

I know visual studios does this for some of their function calls but wasn't sure if it was something that was possible to do on my own.

Addition to the answers below: default parameter value is a .NET 3.5 C# feature. I see you are using VS2010. http://stackoverflow.com/questions/3602234/c-sharp-default-parameters — Csaba Toth, Jun 28 '13 at 18:17

score 4 · Accepted Answer · answered Jun 28 '13 at 14:20

4

Yes you can overload a function:

public void Function() {

}

public void Function(string argument) {

}

public void Function(string argument, string argument) {

}

Or you can use params:

public void Function(params string[] arguments) {

}

You can then invoke the function via:

 Function("argument1", "argument2", "argument3");

answered Jun 28 '13 at 14:20

Darren

This is perfect, exactly what I wanted to know, Thanks. As soon as it lets me, I'll select this as the correct answer. – Ian Oswald Jun 28 '13 at 14:26

score 0 · Answer 2 · answered Jun 28 '13 at 14:23

As Darren wrote, you can create overloads in C#

With the introduction of optional parameters and default values, some of these can be reduced to a single implementation:

For instance,

 public void Foo(string param1, int param2)
 {
   ...
 }

 public void Foo(string param1)
 {
   Foo(param1, 12);
 }

Can be replaced by

 public void Foo(string param1, int param2 = 12)
 {
   ...
 }

2 Answers2