Is there a way to get Go to compile and link in one step (6g and 6l at once)?

Question

I'm trying to search Google but the keyword 'go' makes it difficult to find any useful answers. Reading the http://golang.org/ page doesn't turn up anything useful either.

Right now, I have a simple function in my bash.rc:

function gogo() {
    6g -o gotmp.tmp $@;
    6l -o go.out gotmp.tmp;
    rm -f gotmp.tmp;
}

However, this is not perfect. It would be nice for something built in (perhaps something like gogcc but using 6g/6l backend).

Thanks!

score 6 · Accepted Answer · edited May 23 '17 at 11:55

6

Do you have a reason to not use a build system?

There is a ready made Makefile in $GOROOT/doc/. Other build systems: What build systems work with Go?

edited May 23 '17 at 11:55

Community

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answered Nov 15 '09 at 02:14

Isaiah

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Thanks. I think the Makefile should work for what I'm doing. Scons looks good, too. – Nick Presta Nov 15 '09 at 08:25

Is there a way to get Go to compile and link in one step (6g and 6l at once)?

1 Answers1