converting nsinteger to nsnumber strange number

Question

I have a method that receives an nsinteger, then I need to convert it to a nsnumber, but I get a really strange number, my code is:

+(TarefaMR *)GetTask:(NSInteger *)idTask {   
    NSLog(@"idTask %@",[NSNumber numberWithInteger:idTask]);
    NSInteger *tt=111;    
    NSLog(@"tt %@",[NSNumber numberWithInteger:tt]); 
}

my idtask is 888 and I get a 203513664 while the tt variable is working , I get the 111, what can be the problem?

+(TarefaMR *)GetTask:(NSInteger *)idTask did you mean +(TarefaMR *)GetTask:(NSInteger)idTask — 0x8badf00d, Jun 25 '13 at 12:20
`NSInteger` is a primitive type, a typedef to `int` or `long long`. It's **not a class.** Why you people don't read the documentation? — , Jun 25 '13 at 12:21
@user2069142 yes, it does if you look carefully what it means. Don't use a pointer to an NSInteger or you will just get the memory address instead of the value — Mario, Jun 25 '13 at 12:39
i removed the * and i keep getting this number : 174447376 instead off 888 — edounl, Jun 25 '13 at 12:58
Your doing something else wrong then! How to you call the method? — Mario, Jun 25 '13 at 13:15
i have and object then use : currentTask.noteId=[[allDataDictionary objectForKey:@"noteId"]integerValue]; and i call the method like this [client GetTask:[current noteId]] in didSelectRowAtIndexPath; — edounl, Jun 25 '13 at 14:05
well, it might be, but i found the problem, it hadnt anything to do with this, sorry for the basic question... — edounl, Jun 25 '13 at 16:59

score 3 · Accepted Answer · edited Jun 25 '13 at 12:26

3

You shouldn't use NSInteger as a reference. Try removing the * from behind every mention to NSInteger you do. Remember, NSInteger are not objects, they're just a cool way to name "int"s :)

edited Jun 25 '13 at 12:26

Girish

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answered Jun 25 '13 at 12:20

Bartserk

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converting nsinteger to nsnumber strange number

1 Answers1