Is this function considered terminated?

Question

Suppose the code goes like this

void b()
{
...
}
void c()
{
    b();
}

is c considered terminated after the call to b but b has not yet terminated?

c() will be terminated after b() is terminated - at least in the general concept you are talking about — Grzegorz Piwowarek, Jun 23 '13 at 13:45
A compiler might optimize your code so it terminates `c()` before `b()`, but you shouldn't think in optimized code. — Tom van der Woerdt, Jun 23 '13 at 13:46
@Tom van der Woerdt: What kind of optimization will return calling function, before the return from called function? — sukumarst, Jun 24 '13 at 01:11
@CancerSoftware [Tail call optimization](https://en.wikipedia.org/wiki/Tail-call_optimization) — Tom van der Woerdt, Jun 24 '13 at 09:49

score 1 · Accepted Answer · answered Jun 23 '13 at 13:45

1

You can verify using debug messages:

void b()
{
    cout << "b()" << endl;
}
void c()
{
    b();
    cout << "ended c()" << endl;
}

So, the ended c() appears after b() message.

answered Jun 23 '13 at 13:45

Ionică Bizău

score 0 · Answer 2 · answered Jun 23 '13 at 13:44

0

No, c() is not supposed to be terminated before b() is terminated in general case.

answered Jun 23 '13 at 13:44

Alex

2 Answers2