POSIX regular expression for showing line if contains a string

Question

what is the regular expression for showing whole line if it contains particular string?

source string is "ABC: i am your father" and I need to show everything on the line after "ABC:" so the final output is "i am your father".

Thanks.

What did you tryied so far ? – DontVoteMeDown Jun 21 '13 at 20:31 — DontVoteMeDown, Jun 21 '13 at 20:31

Ro Yo Mi · Answer 1 · 2013-06-22T00:17:04.310

0

This regex will put everything after abc: into capture group 2

^ABC:[[:space:]](.*)

Input text: ABC: i am your father

Matches:

[0] => ABC: i am your father
[1] => i am your father

edited Jun 22 '13 at 00:17

answered Jun 21 '13 at 21:14

Ro Yo Mi

i think your solution is not POSIX style. for validation go to http://www.rexv.org/ – user2509975 Jun 21 '13 at 21:44
Sorry, I missed the posix part of the question. On a side note that rexv.org is pretty cool. – Ro Yo Mi Jun 22 '13 at 00:18

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