How to open an application

Question

I wrote this code to open my application - the name of the executable is C# code analyser.exe. When I start it under Windows 7 (I don't know how this behaves under different versions of Windows), it displays the following message.

Do you want to allow to following program to make changes to this computer?

So I want Windows to not display it to me! What must I do to prevent this message from displaing?

System.Diagnostics.Process Process = new System.Diagnostics.Process();
Process.StartInfo.FileName = (System.IO.Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.ApplicationData), "C# code analyser.exe"));
Process.StartInfo.WorkingDirectory = (System.IO.Path.Combine(Environment.GetFolderPath(Environment.SpecialFolder.ApplicationData), "C# code analyser.exe"));
Process.Start();

Executables belong in c:\program files, not c:\programdata. – Hans Passant Jun 21 '13 at 00:15 — Hans Passant, Jun 21 '13 at 00:15

Manoj · Answer 1 · 2013-06-24T06:50:57.637

2

Use this instead of your code

System.Diagnostics.Process oProcess = new System.Diagnostics.Process();
oProcess.StartInfo.FileName = "HelloWorld.exe";
oProcess.Start();

or you can pass administrator username & password this way

Process.Start(path + "HelloWorld.exe", uname, password, domain);

edited Jun 24 '13 at 06:50

answered Jun 21 '13 at 09:37

Manoj

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score 0 · Answer 2 · answered Jun 21 '13 at 11:53

This analyzer project, most probably, have a manifest that request administration mode to run. This means that it will keep raising UAC if the starter process(your app) is not elevated.

You can try run you application as an administrator (right click-run as admin) and then the analyzer will inherit the elevation and it will not raise the UAC message.

How to open an application

2 Answers2