How to open an app directly without showing UIActivityViewController in ios?

Question

I am having an app in which I want to open native application without opening UI Activityviewcontroller.

On click of a button, I want to open the native app.

I have set the URL of an app on click of a button, but still it is showing an activityviewcontroller.

How to avoid UIActivityViewController?

Thanks in advance.

Edited

I am sharing an image on instagram on click of a button.

Here is my code.

NSURL *instagramURL = [NSURL URLWithString:@"instagram://"];

                if ([[UIApplication sharedApplication] canOpenURL:instagramURL])
                {

                    CGRect rect = CGRectMake(0 ,0 , 0, 0);
                    UIGraphicsBeginImageContextWithOptions(self.view.bounds.size, self.view.opaque, 0.0);
                    [self.view.layer renderInContext:UIGraphicsGetCurrentContext()];

                    UIGraphicsEndImageContext();
                    NSArray* paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
                    NSString* documentsDirectory = [paths objectAtIndex:0];

                    imagename=[NSString stringWithFormat:@"FameFace.ig"];
                    NSString* fullPathToFile = [documentsDirectory stringByAppendingPathComponent:imagename];
                    ////NSLog(@"%@",fullPathToFile);

                    igImageHookFile = [[NSURL alloc] initWithString:[[NSString alloc] initWithFormat:@"file://%@", fullPathToFile]];

                    self.dic.UTI = @"com.instagram.photo";
                    self.dic = [self setupControllerWithURL:igImageHookFile usingDelegate:self];
                    self.dic=[UIDocumentInteractionController interactionControllerWithURL:igImageHookFile];
     self.dic.annotation = [NSDictionary dictionaryWithObject:@"Image" forKey:@"InstagramCaption"];
   [self.dic presentOpenInMenuFromRect: rect    inView: self.view animated: YES ];

enter image description here

As shown in the screenshot it opens up in UIActivityView.

Is it possible that if I click on a button it instantly navigates me to the native app without showing that ActivityViewController?

score 4 · Answer 1 · answered Jun 06 '13 at 13:08

4

You can open an app using [[UIApplication sharedApplication] openURL:appURL]

It would look something like this in your case:

NSURL *instagramURL = [NSURL URLWithString:@"instagram://"];

if ([[UIApplication sharedApplication] canOpenURL:instagramURL])
{
    NSURL * openInstagramURL = nil;
    //TODO: construct your proper instagram URL here. 
    [[UIApplication sharedApplication] openURL:openInstagramURL];
}

The key thing is that you have to properly construct your URL such that the receiving application, in this case Instagram would perform the correct action.

answered Jun 06 '13 at 13:08

Engin Kurutepe

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NSURL * openInstagramURL = nil; [[UIApplication sharedApplication] openURL:openInstagramURL]; I added this two lines but it still showing me tha ActivityView. – Manthan Jun 06 '13 at 13:16
1

first of all you have to construct the proper URL for instagram, nil is obviously not going to work. And second you have to delete your code with `UIDocumentInteractionController` – Engin Kurutepe Jun 06 '13 at 13:27

How to open an app directly without showing UIActivityViewController in ios?

1 Answers1