I'm trying to copy a remote file (image PNG, GIF, JPG ...) to my server. I use Guzzle since I sometimes get 404 with copy() even if the file exists and I also need to do a basic auth. This script is within a long script launched in command triggered by a cron job. I'm pretty new to Guzzle and I successfully copy the image but my files have wrong mime type. I must be doing something wrong here. Please suggest me a good way to do this (including checking success/failure of copy and mime type check). If file has no mime type I would pop an error with details informations.
Here is the code:
$remoteFilePath = 'http://example.com/path/to/file.jpg';
$localFilePath = '/home/www/path/to/file.jpg';
try {
$client = new Guzzle\Http\Client();
$response = $client->send($client->get($remoteFilePath)->setAuth('login', 'password'));
if ($response->getBody()->isReadable()) {
if ($response->getStatusCode()==200) {
// is this the proper way to retrieve mime type?
//$mime = array_shift(array_values($response->getHeaders()->get('Content-Type')));
file_put_contents ($localFilePath , $response->getBody()->getStream());
return true;
}
}
} catch (Exception $e) {
return $e->getMessage();
}
When I do this my mime type is set to application/x-empty
Also it looks like when status is different from 200 Guzzle will automatically throw an exception. How can I stop this behaviour and check status myself so I can custom error message?
EDIT: This was for Guzzle 3.X Now this is how you can do it using Guzzle v 4.X (works as well with Guzzle 6)
$client = new \GuzzleHttp\Client();
$client->get(
'http://path.to/remote.file',
[
'headers' => ['key'=>'value'],
'query' => ['param'=>'value'],
'auth' => ['username', 'password'],
'save_to' => '/path/to/local.file',
]);
Or using Guzzle stream:
use GuzzleHttp\Stream;
$original = Stream\create(fopen('https://path.to/remote.file', 'r'));
$local = Stream\create(fopen('/path/to/local.file', 'w'));
$local->write($original->getContents());
This looks great. Is there better/proper solution when using Guzzle 4?