C++11 is_same type trait for templates

Question

Is it possible to check that type T is an std::array of arbitrary type and size?

I can check for a particular array, for instance:

is_same<T, std::array<int,5>>::value

But I'd like to check that T is any instantiation of std::array. Something like below (which, of course, does not compile):

is_same<T, std::array>::value

Is there a way to achieve this (maybe not using is_same)?

You can write a generic `is_same_template` and say `is_same_template ` . The compiler must support the c++11 injected class name rules though. — Johannes Schaub - litb, Jun 04 '13 at 20:34

score 58 · Accepted Answer · answered Jun 03 '13 at 20:35

58

You have to write your own, but it's simple:

template<typename>
struct is_std_array : std::false_type {};

template<typename T, std::size_t N>
struct is_std_array<std::array<T,N>> : std::true_type {};

answered Jun 03 '13 at 20:35

jrok

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C++11 is_same type trait for templates

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