PHP dynamic instanciating

Question

I've an object which returns a string and I would like instanciate another object with the string returned, why in PHP I can't instanciate this way ?

For Example:

// getController() returns a string name controller
$c = new $this->router->getController() ;


// I have to do this way:
$controller = $this->router->getController() ;
$c = new $controller() ;

Thank you for your help.

But you can! What error specifically do you receive from this code? — Maxim Kumpan, Jun 03 '13 at 14:01
I do it like in your example all time, seems to be the easiest and most reliable way. — TCB13, Jun 03 '13 at 14:02
Oh, wait. I think I misunderstood the question. You want to do it directly, like $c = new {$this->router->getController()}; ? — Maxim Kumpan, Jun 03 '13 at 14:02
This seems like the most clear method of doing this, though. — crush, Jun 03 '13 at 14:05

score 0 · Answer 1 · answered Jun 03 '13 at 14:02

0

It's a syntax thing. I think I remember seeing an RFC to allow more dynamic class instantiation, but assigning to a variable first gets the job done, no?

answered Jun 03 '13 at 14:02

landons

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Yeah, you did: https://wiki.php.net/rfc/instance-method-call. – TCB13 Jun 03 '13 at 14:05

PHP dynamic instanciating

1 Answers1