Extract time from ISO8601 string

Question

I have an ISO8601 string

2013-05-11 05:54:07.589698

Is there anyway to extract just the time from this without string manipulation?

thanks h2c03! Sometimes I just need to know where to look. pardon the ignorance and thanks for the help. And sorry this isn't a ISO8601 formatted timestamp string? — user2159691, Jun 03 '13 at 05:48
ok so from what I've read, there's no way to turn this 2013-05-11 05:54:07.589698 into this 05:54:07 without manipulating the string first two separate the two. Is this correct? — user2159691, Jun 03 '13 at 06:47

score 2 · Accepted Answer · answered Jun 03 '13 at 07:06

There are many answers for similar questions, just posting this answer incase you haven't found it yet

NSString *inputString = @"2013-05-11 05:54:07.589698";

NSDateFormatter *dateFormatter = [NSDateFormatter new];
[dateFormatter setTimeZone:[NSTimeZone timeZoneWithAbbreviation:@"UTC"]];
[dateFormatter setLocale:[[NSLocale alloc]initWithLocaleIdentifier:@"en_US_POSIX"]];
[dateFormatter setDateFormat:@"yyyy-MM-dd HH:mm:ss.SSSSSS"];

NSDate *date = [dateFormatter dateFromString:inputString];
[dateFormatter setDateFormat:@"HH:mm:ss"];
NSString *timeString = [dateFormatter stringFromDate:date];

NSLog(@"%@",timeString);

god I love you...so very very much. THANK YOU! – user2159691 Jun 03 '13 at 07:10 — user2159691, Jun 03 '13 at 07:10

Extract time from ISO8601 string

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