Python time from a 6 digit number

Question

I have a series of six digit numbers in this array:

a = np.array((121011,121020,121025,121030,121032,121037,121234))

How do I get a time from each of the six digit numbers? e.g.:

12:10:11

I wish to use the time for calculations.

No, I wish the time to be numbers so that I can use them for calculations. — Jay, Jun 02 '13 at 15:55

score 3 · Accepted Answer · answered Jun 02 '13 at 16:04

Since you said you wanted to do calculations, you probably want time objects, not strings.
See the documentation.

for number in a:
    h = number // 10000
    m = (number // 100) - (h * 100)
    s = number % 100
    t = time(h,m,s)
    # then do whatever you want with t

score 1 · Answer 2 · answered Jun 02 '13 at 15:26

1

Convert to strings, split and print out would work:

for number in a:
    str_number = str(number)
    print('{}:{}:{}'. format(str_number[:2], str_number[2:4], str_number[4:]))


12:10:11
12:10:20
12:10:25
12:10:30
12:10:32
12:10:37
12:12:34

answered Jun 02 '13 at 15:26

Mike Müller

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Python time from a 6 digit number

2 Answers2