Assembly rdtsc x64 ubuntu

Question

I'm trying to use rdtsc function but i've got weird numbers. I'm trying to call this function from C code and pass the tick back to function. Can you tell me if im doing it right or not ?

Asm code:

.text

.globl czas
.type czas, @function

czas:
pushq %rbp
movq %rsp, %rbp
xor %rax,%rax;
cpuid
rdtsc
popq %rbp
ret

C code:

unsigned long long Czas;
Czas=czas();

yes, but i've got something like this: Czas dla FPU: 18446744069679515163 — Gravian, May 31 '13 at 13:34
Have you tried [using this instead](http://www.cs.wm.edu/~kearns/001lab.d/rdtsc.html) ? — Michael, May 31 '13 at 13:37

score 3 · Answer 1 · answered May 31 '13 at 14:29

3

rdtsc returns result in edx:eax even in 64 bit mode, but C calling convention expects result in rax. You have to pack the result yourself. Note you don't typically need a stack frame for this. Something like:

cpuid
rdtsc
shl $32, %rdx
or %rdx, %rax
ret

answered May 31 '13 at 14:29

Jester

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For a bit of historical context, http://gcc.gnu.org/bugzilla/show_bug.cgi?id=21249 (not a bug because `rdtsc` in 64bit mode works differently ... but people stumble over this for the last ten years) – FrankH. Jun 01 '13 at 10:13

score 0 · Answer 2 · answered May 31 '13 at 14:28

What kind of type is your function? It should be UINT64. rdtsc return low 32 bits in EAX and high 32 bits in EDX register. So is you wont result in RAX than perform:

  shl   rdx, 32     //left shift for 32 bits
  or    rax, rdx    //Compose both registers in 64 bit RAX

after executing rdtsc instruction.

Assembly rdtsc x64 ubuntu

2 Answers2