Strange behaviour of an array returned by a function

Question

Why does this code work:

$row = $stmt->fetch();
$result = array("status"=>"0", "uid"=>($row["id"]));

And this one does not:

$result = array("status"=>"0", "uid"=>(($stmt->fetch())["id"]));

Sorry for the duplicate and thanks for the answer. – Valentin Solina May 31 '13 at 12:00 — Valentin Solina, May 31 '13 at 12:00

score 2 · Accepted Answer · edited May 31 '13 at 11:54

2

Since PHP 5.4 it's possible to do what you did.

getSomeArray()[$someKey]

Prior to PHP 5.3, you'll need to use a temporary variable.

edited May 31 '13 at 11:54

Matt Browne

answered May 31 '13 at 11:51

imulsion

Cool, I didn't know they had added that in PHP 5.4. – Matt Browne May 31 '13 at 11:53
@MattBrowne I know, its quite useful – imulsion May 31 '13 at 11:54
2

Why do people keep downvoting this? In PHP 5.3 or below a temporary variable is indeed the only way to accomplish this. – Matt Browne May 31 '13 at 11:56
@MattBrowne I am close to exploding. I was so happy when I saw that big 3... – imulsion May 31 '13 at 11:56
@MattBrowne it's especially weird since all the downvoters lost 1 rep... – imulsion May 31 '13 at 11:57
+1 +55/-8 Four upvotes + accept / 4 downvotes :P – Vivek Sadh May 31 '13 at 12:06
@Vivek i can live with that ;) – imulsion May 31 '13 at 12:07
Though i didn't really understand it but after reading the comments i thought that its a good answer and deserves an Upvote ;) – Vivek Sadh May 31 '13 at 12:08
1

@Vivek you didn't understand it? Join the club :) – imulsion May 31 '13 at 12:09
@imulsion After visiting that link i understood it :) – Vivek Sadh May 31 '13 at 12:13

1 Answers1