Parsing RSS in Python

Question

I am trying to parse rss feed using python.

The rss feed has the format:

 <rss xmlns:media="http://search.yahoo.com/mrss/" version="2.0">
      <channel>
                <title>Yahoo! News - Latest News & Headlines</title>
                <link>http://news.yahoo.com/</link>
                <description>...</description>
                <language>en-US</language>
                <copyright>Copyright (c) 2013 Yahoo! Inc. All rights reserved</copyright>
                <pubDate>Thu, 30 May 2013 21:14:41 -0400</pubDate>
                <ttl>5</ttl>
                <image>...</image>
                <item>...</item>
                <item>...</item>
                <item>...</item>
      </channel>
 </rss>

I need to extract some details of the <items>.

Using print feed['channel']['title'] etc I can get details of those blocks occurring only once. How do I extract details of the items? feed['channel']entries[0] or feed['channel']['items[0]] etc do not seem to work.

I assume you are using some sort of XML or RSS parsing library for this? — sberry, May 31 '13 at 04:16
Is this what you need? http://pythonhosted.org/feedparser/common-rss-elements.html#accessing-common-channel-elements "The items are available in d.entries, which is a list." — Radio-, May 31 '13 at 04:29

score 1 · Answer 1 · edited Apr 16 '19 at 00:02

1

feed.entries[doc_iter]['title']

Seems to work. The doc_iter mentions the ith item.

edited Apr 16 '19 at 00:02

nick

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answered May 31 '13 at 04:29

Manas Paldhe

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Parsing RSS in Python

1 Answers1