Express.js route parameter with slashes

Question

I have an application which serves file listings.

The application must respond to following routes:

/company/:id
/company/:id/dir
/company/:id/dir/dir

Here /company/:id is a route with no path specified e.g a root directory. I was thinking for something like app.get('/company/:id/:path', ... which obviously doesn't work.

How can I define a route which responds to all of the examples?

Same as: http://stackoverflow.com/questions/10020099/express-js-routing-optional-spat-param/14481168 ? — Andreas Hultgren, May 30 '13 at 07:09
I disagree with the duplicate because https://stackoverflow.com/questions/10020099/express-js-routing-optional-splat-param is a subset of this for an optional splat. This one does not talk about optional, just the splat part. — Ciro Santilli OurBigBook.com, Aug 04 '21 at 13:22

score 84 · Accepted Answer · edited Jan 24 '19 at 18:27

84

Use /company/:id* (note trailing asterisk).

Full example

var express = require('express')();

express.use(express.router);

express.get('/company/:id*', function(req, res, next) {
    res.json({
        id: req.params['id'],
        path: req.params[0]
    });    
});

express.listen(8080);

edited Jan 24 '19 at 18:27

Linus Unnebäck

23,234
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answered May 30 '13 at 07:03

Prinzhorn

22,120
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5

Or `/company/:id*` (without the slash). – robertklep May 30 '13 at 08:06
@robertklep perfect, that handles all cases – Prinzhorn May 30 '13 at 08:14
1

The route parameters is { '0': 'adfadf/fasdfa', slug: 'aaaa' } when I request /aaaa/adfadf/fasdfa . i don't know where the key '0' come from – Như Là Mơ Jan 11 '19 at 08:51
4

@NhưLàMơ `:id*` turns params into an array. So the :slug part is given the "slug" named property (assuming your path is `/:slug*`) in the params object, and then the 0th index is the rest of the matched part of the path. – Redmega Jul 15 '19 at 22:21

Express.js route parameter with slashes

1 Answers1

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