guide me in dividing the number by 10 and later converting into a string

Question

#include<stdio.h>
int main()
{
int num = 255;
num = num / 10;
char buf[5];
itoa(num, buf,10);
printf("%s", buf);
return 0.
}

I am trying to divide the integer number by 10 but I am getting a solution of 25 ( I should get 25.5). Later I am converting this into string by integer to ASCII function. I have problem to divide that number by 10.

integer does not have a decimal point. What exactly are you trying to do? — Kangkan, May 27 '13 at 12:02
You need to start by understanding what an [integer](http://en.wikipedia.org/wiki/Integer) is. — Clifford, May 28 '13 at 09:03
There have been some answers for your question, please accept one. — Werner Henze, Oct 02 '13 at 12:51

score 2 · Answer 1 · answered May 27 '13 at 12:02

2

you need to use a float variable to get floating point results.

try

float num = 255;
num = num / 10;

answered May 27 '13 at 12:02

motz

103
1
6

Or, more idiomatically, `num /= 10;` – May 27 '13 at 12:03
later how to convert into string ?? – suhas sjbit May 27 '13 at 12:13

score 1 · Answer 2 · answered May 27 '13 at 12:03

1

When storing a floating value to an integer the decimal part is thrown away. So in num = num / 10; num will be 25 because it is an int.

answered May 27 '13 at 12:03

Thomas Kaliakos

3,274
4
25
39

if I use double insteads of int, then how to convert into string ?# – suhas sjbit May 27 '13 at 12:11
@chux `float` is automatically upcast to `double`. `%lg` is not a valid format specifier – Tom Tanner May 27 '13 at 13:45
@Tom Tanner, Yes of course you are correct. I was thinking of scanf(). – chux - Reinstate Monica May 27 '13 at 13:59

score 1 · Answer 3 · answered May 27 '13 at 12:28

An integer divided by an integer is an integer, so you get 25 as a result. You need to cast divisor or denominator to float or double first.

To output a float to console you can use printf with %f, %F, %e, %E, %g or %G format string. You might also want to specify a width and precision (see printf).

If you really need a string buffer, you can use sprintf to write the result to a buffer.

#include<stdio.h>
int main()
{
    float num = 255f;
    num = num / 10;
    printf("%f\n", num);
    return 0.
}

score 0 · Answer 4 · edited May 27 '13 at 12:43

0

#include <stdio.h>
#include <string.h>

char buffer[20];

void main() {
    float num = 255;
    num = num / 10;

    sprintf(buffer, "%g", num );

    printf("%s",buffer);
}

edited May 27 '13 at 12:43

JBL

12,588
4
53
84

answered May 27 '13 at 12:17

Paramesh

1

score 0 · Answer 5 · answered May 27 '13 at 12:45

Firstly, num is (as pointed out) an integer, so cannot take fractional values.

Secondly, itoa is not standard. You should use snprintf (which is not only standard, it is not susceptible to buffer overflows).

So:

#include <stdio.h>

int main()
{
    float num = 255;
    num = num / 10;

    char buf[5];
    snprintf(buf, sizeof(buf), "%g", num);
    printf("%s", buf);
    return 0.
}

will do what you want.

guide me in dividing the number by 10 and later converting into a string

5 Answers5