Square root and def function?

Question

As I've progressed a little more in Python I thought I would try out the define function. I've made this simple square root calculator. Please explain as simple as you can?

import math

def mathprob(x):
    math.sqrt(x)

yn = input()
num = int(input("Enter number to be square rooted."))

if yn == 'sqrt':
    ans = mathprob(num)
    print(ans)

elif yn == '':
    print("bye! :(")
    quit()

Haha sorry. But when I type in the number to be square rooted, the program just stops — user2340615, May 23 '13 at 19:48
Are you sure that you're typing `'sqrt'` before you enter the number? If you're doing that, you should at least see `None` printed. — mgilson, May 23 '13 at 19:55

score 3 · Accepted Answer · answered May 23 '13 at 19:51

3

You need to return the value from your function, otherwise it returns None:

def mathprob(x):
     return math.sqrt(x)

answered May 23 '13 at 19:51

mgilson

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score 1 · Answer 2 · answered May 23 '13 at 19:53

1

You need to actually return something from your function, you can do it like this:

def mathprob(x):
    return math.sqrt(x)

answered May 23 '13 at 19:53

Mezgrman

876
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The OP is probably using Python 3, given the use of print(), therefore raw_input is not required. – Daniel Roseman May 23 '13 at 19:54
Oh, has that changed in Python 3? I didn't know that. – Mezgrman May 23 '13 at 19:54

Square root and def function?

2 Answers2