How to fill and access to std::map, funcPtr>?

Question

I would like to know how to fill this type of map and mainly the way to access to the function pointer.

The map :

enum enum1
{
   val11,
   val12,
   val13
};

enum enum2
{
   val21,
   val22,
   val23
};

typedef void(MyClass::*funcPtr)();

std::map<std::pair<enum1, enum2>, funcPtr> map;

I fill it like this, it seems to work:

map.insert(std::make_pair(std::make_pair(val11, val21), &MyClass::init));

But I can't access to the function like this:

map[std::make_pair<val11, val21>]();

What am I doing wrong?

score 2 · Accepted Answer · answered May 22 '13 at 10:03

2

You are using the wrong parentheses with make_pair and need to call the member function on some instance of MyClass (using the .* or ->* operators):

MyClass obj;
(obj.*map[std::make_pair(val11, val21)])();

answered May 22 '13 at 10:03

Joseph Mansfield

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I'm trying : `this->*(map[std::make_pair(val11, val21)])();` it throw me an error : `error: must use ‘.*’ or ‘->*’ to call pointer-to-member function in [...]` – Elfayer May 22 '13 at 10:10
It's just a precedence issue. Try: `(this->*map[std::make_pair(val11, val21)])();` – Joseph Mansfield May 22 '13 at 10:10
Yep, my mistake, forgot the first parenthesis. ^^ – Elfayer May 22 '13 at 10:13

How to fill and access to std::map, funcPtr>?

1 Answers1