I'm attempting to generate a class than can read any type of serialized XSD/XML code. Since I have about 1000 different data defintions, I would love to make the XmlLoader
class generic.
However, in the auto-generated serialized code, the way to obtain a pointer to the in-memory data is difficult for me to grasp.
The code:
template <class XmlType>
class XmlLoader {
public:
XmlLoader(const std::string &filename, const std::string &xsd) :
filename(filename),
xsd(xsd) {
try {
this->initialize();
} catch (const xml_schema::exception &e) {
ERROR("Unable to parse [%s], aborting\n", filename.c_str());
} catch (const std::invalid_argument &e) {
ERROR("Unable to locate [%s], aborting\n",
std::string(Component::getJarssXSDDirectory() + xsd).c_str());
}
}
std::auto_ptr<XmlType> xmlInstance;
private:
void initialize() {
std::string schema = Component::getJarssXSDDirectory() + xsd;
if (!Application::validatePath(schema)) {
throw std::invalid_argument("XSD cannot be found");
}
xml_schema::properties props;
props.no_namespace_schema_location(schema);
xmlInstance = std::auto_ptr<XmlType > (XmlType_(filename, 0, props));
}
std::string filename;
std::string xsd;
};
The problem lies with this line: xmlInstance = std::auto_ptr<XmlType > (XmlType_(filename, 0, props));
If I were to do this by hand, it would look something like:
xmlInstance = std::auto_ptr<XmlType>(XmlType_(filename, 0, props));
Notice the _
for the function on XmlType.
When I try to template this, the compiler states that XmlType_
isn't a type, nor was it included in the argument template.
Since XmlType_
isn't a type, it's a function generated by the XSD serializer, how can I pass this through the template? I've never encountered anything like this before.
Any ideas?