Python: ConfigParser.NoSectionError: No section: 'TestInformation'

Question

I am getting ConfigParser.NoSectionError: No section: 'TestInformation' error using the above code.

def LoadTestInformation(self):        
    config = ConfigParser.ConfigParser()    
    print(os.path.join(os.getcwd(),'App.cfg'))

    with open(os.path.join(os.getcwd(),'App.cfg'),'r') as configfile:       
        config.read(configfile)
        return config.items('TestInformation')

The file path is correct, I have double checked. and the config file has TestInformation section

[TestInformation]

IEPath = 'C:\Program Files\Internet Explorer\iexplore.exe'

URL = 'www.google.com.au'

'''date format should be '<Day> <Full Month> <Full Year>'

SystemDate = '30 April 2013'

in a app.cfg file. Not sure what I am doing wrong

In your question's last line you say you have put all this in `app.cfg` but in your code you are opening `App.cfg`. I'll take that as a typo. — RedBaron, May 17 '13 at 05:13
Try using `readfp()` instead of `read`. `read()` expects a list of filenames, `readfp()` expects a file object — RedBaron, May 17 '13 at 05:15

score 10 · Accepted Answer · answered May 17 '13 at 05:27

Use the readfp() function rather than read() since you are opening the file before reading it. See Official Documentation.

def LoadTestInformation(self):        
    config = ConfigParser.ConfigParser()    
    print(os.path.join(os.getcwd(),'App.cfg'))

    with open(os.path.join(os.getcwd(),'App.cfg'),'r') as configfile:       
        config.readfp(configfile)
        return config.items('TestInformation')

You can continue to use read() if you skip the file opening step and instead the full path of the file to the read() function

def LoadTestInformation(self):        
    config = ConfigParser.ConfigParser()    
    my_file = (os.path.join(os.getcwd(),'App.cfg'))
    config.read(my_file)
    return config.items('TestInformation')

Python: ConfigParser.NoSectionError: No section: 'TestInformation'

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