Using cycle to Django?

Question

I am developing a Django application, i had some problem,

I hope to do the following effects on Django,

<div id='cssmenu'>
<ul>
<li class='active'><a href='#'><span>Home</span></a></li>
   <li><a href='#'><span>Products</span></a></li>
   <li><a href='#'><span>Company</span></a></li>
   <li class='last'><a href='#'><span>Contact</span></a></li>
</ul>
</div>

Django Code,

<div id='cssmenu'>
{% for child in children %}
{% cycle 'active' 'last' as cssmenu silent %}
<li class="{{ cssmenu }}">
    <a href="{{ child.attr.redirect_url|default:child.get_absolute_url }}">{{ child.get_menu_title }}</a>
    {% if child.children %}
    <ul>
        {% show_menu from_level to_level extra_inactive extra_active template "" "" child %}
    </ul>
    {% endif %}
</li>
{% endfor %}
</div>

Could you help me?

i dont think that is the right way of using cycle. https://docs.djangoproject.com/en/dev/ref/templates/builtins/#cycle — karthikr, May 14 '13 at 02:30
Thank you Jesse,http://dl.dropboxusercontent.com/u/2057717/Screenshots/bu50.png — user962105, May 14 '13 at 03:17

score 0 · Answer 1 · answered May 14 '13 at 09:19

That's not what cycle is for: it's for alternating between two or more alternatives. You don't want that at all.

Instead, just use the forloop attributes:

{% for child in children %}
    <li class="{% if forloop.first %}active{% elif forloop.last %}last{% endif %}">...</li>
{% endfor %}

Although I suppose you don't want the first one to always be active, but you haven't given any information about how you do want to determine where 'active' goes.

Using cycle to Django?

1 Answers1