check if decimal $var is_int, then run round()

Question

Im trying to write a function that will check if a $var is a number (i was trying to trying to use is_int()) and if it is then run round().

The only problem is that for round() im using a number like 123.25, which as in understand isn't an int, because of the the decimal places, so i cant use is_int().

Any idea how i can get this to work ?

$var = 1123.25;

function round_num($var) {
    if(is_int($var)) {
        return round($var, 2);
    }
}

echo round_num($var);

[`is_numeric()`](http://php.net/manual/en/function.is-numeric.php)? I'd also suggest you add `!empty($var)` to your condition so that it doesn't give a notice if the `$var` is empty — billyonecan, May 08 '13 at 12:03

score 1 · Accepted Answer · answered May 08 '13 at 12:03

1

Check using function is_numeric.

function round_num($var) {
    if(is_numeric($var)) {
        return round($var, 2);
    }
}

answered May 08 '13 at 12:03

Rikesh

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check if decimal $var is_int, then run round()

1 Answers1