a
and b
are both rpy2 IntVector
s:
<IntVector - Python:0x10676dfc8 / R:0x7fc714d64948>
[ 81, NA_integer_, NA_integer_, ..., 120, 46, NA_integer_]
How can I calculate the b - a
difference? I want the result as an IntVector
.
a
and b
are both rpy2 IntVector
s:
<IntVector - Python:0x10676dfc8 / R:0x7fc714d64948>
[ 81, NA_integer_, NA_integer_, ..., 120, 46, NA_integer_]
How can I calculate the b - a
difference? I want the result as an IntVector
.
subtract = r('''function(x, y) x - y''')
subtract(b, a)
The good about this solution is that it can not only handle IntVectors, but any R type. The bad is that passing commands as strings to the R interpreter is ugly.
Try using the R operator attribute .ro:
In [1]: from rpy2 import robjects
In [2]: x = robjects.IntVector(range(10))
In [3]: y = robjects.IntVector(range(10))
In [4]: x.ro-y
Out[4]:
<IntVector - Python:0x1067d3830 / R:0x102d6ef20>
[ 0, 0, 0, ..., 0, 0, 0]
In [5]: x.ro+y
Out[5]:
<IntVector - Python:0x1067d3cf8 / R:0x102d6eec8>
[ 0, 2, 4, ..., 14, 16, 18]