34

I'm checking out angular routing.

http://www.bennadel.com/blog/2420-Mapping-AngularJS-Routes-Onto-URL-Parameters-And-Client-Side-Events.htm

The examples I see have all the routes be defined in the same file. How do I have various routes be defined in different files / modules?

T J
  • 42,762
  • 13
  • 83
  • 138
Harry
  • 52,711
  • 71
  • 177
  • 261

2 Answers2

57

In AngularJS routes are defined in configuration block. Each AngularJS module can have multiple configuration blocks and you can define routes in each and every configuration block. The final routing for the entire application is a sum of routes defined in all modules.

In practice you can do it like:

angular.module('myModule1', []).config(function($routeProvider){
  //define module-specific routes here
});

angular.module('myModule2', []).config(function($routeProvider){
  //define module-specific routes here
});

angular.module('myApp', ['myModule1', 'myModule2']).config(function($routeProvider){
  //define app-level routes here
});

Regarding the split over files - I guess this largely depends on how you split AngularJS modules in files. What I would recommend is sticking to one-file equals one-module principle.

You can see all this applied to a larger-scale web application in angular-app, an effort to build a reference for a non-trivial application written in AngularJS:

In the mentioned app you can see routes defined in multiple files, ex.:

leiming
  • 494
  • 4
  • 13
pkozlowski.opensource
  • 117,202
  • 60
  • 326
  • 286
  • 1
    What about in the case that a module sets up a route with a resolve property that depends on a provider and that module is specified as a dependency of the main app module? Considering the provider setting would be set in the app module, would the resolve property still work? – Cameron Nov 13 '14 at 20:24
-1

You can make the Angular application with different files without specifing them follow this steps

Step 1: Get the full url

var url = window.location.pathname;

Step 2 Sorting the filename alone

var filename = url.substring(url.lastIndexOf('/')+1);

Step 3 Displaying the result

alert(filename);

I have done this in w3schools try it editor http://www.w3schools.com/code/tryit.asp?filename=FDP3QTCP7V4E