Remove unwanted URL segments in Codeigniter site_url

Question

On the page whose URL is "abc.com/en/login/create_member" using site_url('login') produces a link to "abc.com/en/login/create_member", but the desired URL is "abc.com/en/login/"

I've included the link code and an excerpt from my routes.php file

Thanks in advance for any help on this.

Code:

<a class="link_grad_button" href="<?php site_url('login'); ?>">Login</a></div>

Route Excerpt:

$route[$prepended_lang.'login/(:any)'] = 'login/$1';
// URI like '/en/about' -> use controller 'about'
$route['^(en|br)/(.+)$'] = "$2";
$route['default_controller'] = 'landing';
// '/en', '/de', '/fr' and '/nl' URIs -> use default controller
$route['^(en|br)$'] = $route['default_controller'];

Try to remove `/$1` from `$route[$prepended_lang.'login/(:any)'] = 'login/$1';`... Check if this works — MaNKuR, Apr 28 '13 at 15:53
That did it and I realized that I simply missing an echo so the link was just using the current URL. — jsuissa, Apr 29 '13 at 00:08

score 2 · Accepted Answer · answered Apr 29 '13 at 06:40

Either you add language on the link like

<a class="link_grad_button" href="<?php site_url('en/login'); ?>">Login</a></div>

So, your current expression on your route.php works. i.e.

$route[$prepended_lang.'login/(:any)'] = 'login/$1';

OR

Simply, remove $prepended_lang. from your route.php expression like:

$route['login/(:any)'] = 'login/$1';

This above expression works only when you have a function parameter like

site_url('login/index')

where index works as parameter for (:any), so in case your url is site_url('login') only, you have to add:

$route['login'] = 'login';

before the above expression.

Actually these two expressions are not required on route.php but because of your appended language, these two expressions seems mandatory.

Remove unwanted URL segments in Codeigniter site_url

1 Answers1