How do I combine a char with an int in an NSTextField in Objective-C?

Question

For example, I have the following code, where lblPercent is an NSTextField:

double Progress = progress( Points);
[lblPercent setIntValue:(Progress)];

I set it as integer value so it tosses out the decimal, since for some reason the NSProgressIndicator forces me to use a double. Anyway, in the label adjacent to the progress bar, I want it see the number x% with the percent sign next to it.

I tried standard concatenation techniques but no dice.

score 1 · Answer 1 · answered Apr 23 '13 at 15:07

1

You should use an NSNumberFormatter with the percent style

NSNumberFormatter* formatter = [[NSNumberFormatter alloc] init];
[formatter setNumberStyle: NSNumberFormatterPercentStyle];
// Any other format settings you want
NSString* formattedNumber = [formatter stringFromNumber: [NSNumber numberWithDouble: progress]];

answered Apr 23 '13 at 15:07

JeremyP

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This gave me a rather bizarre number that wasn't what the variable returned for some reason. – Jonathan Weinraub Apr 23 '13 at 20:50
@JonathanWeinraub Using this method to set the field you should use `setStringValue:` on your test field, nt `setIntValue:` – JeremyP Apr 24 '13 at 14:45
Sorry for taking so long to get back to you, I had final exams. Anyway, I now understand what you meant. However, I changed it to what you suggested, the value I get is 600% so the percent sign is there. However, my data that is being returned should be 6% not 600%. So far we are making the best progress on this - I think better progress than I did on my exams :-/ – Jonathan Weinraub May 11 '13 at 06:22
I assume I do this: [lblPercent setStringValue:(formattedNumber)]; because I just realised it isn't that I got padded with zeroes, I got 750% when I gave it data that should had return 1%. – Jonathan Weinraub May 11 '13 at 06:42
@JonathanWeinraub percent style will do the multiplying by 100 for you. formatting 0.06 with percent style should give you 6% because that's what it is. – JeremyP May 15 '13 at 09:34

score 0 · Answer 2 · answered Apr 23 '13 at 14:48

0

try

[lblPercent setText:[NSString stringWithFormat:@"%d%%",[Progress intValue]]];

answered Apr 23 '13 at 14:48

alex

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This gave me bad receiver type double. – Jonathan Weinraub Apr 23 '13 at 15:26
What about [lblPercent setText:[NSString stringWithFormat:@"%f%%",Progress]];? – alex Apr 23 '13 at 15:44
Ok progress! I get the error about **no visible @interface for NSTextField declares in the setText** – Jonathan Weinraub Apr 23 '13 at 15:55

score 0 · Answer 3 · answered Apr 23 '13 at 14:55

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NSMutableString *value = lblPercent.text;
[value appendString:@"%"];
[lblPercent setText:value];

answered Apr 23 '13 at 14:55

Burhanuddin Sunelwala

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This gave me text not found in object of type NSTextField * and also no visible @interface for NSTextfield declares the selector setText – Jonathan Weinraub Apr 23 '13 at 15:27
@JonathanWeinraub: I've edited your question to make it more clear that you are using Cocoa and `NSTextField`, not `UITextField` in iOS. (This answer assumes `lblPercent` is a `UITextField`, and won't work with `NSTextField`). – NSGod Apr 23 '13 at 16:29
@JonathanWeinraub Before your edit, I assumed you were using UILabel as you named it lblPercent. – Burhanuddin Sunelwala Apr 23 '13 at 17:40
@nsgod any ideas on how I can accomplish this now we sorted out the question properly? – Jonathan Weinraub Apr 24 '13 at 01:54

score 0 · Answer 4 · answered Apr 23 '13 at 14:55

0

You can use unicode characters to get the percent sign.

i.e.

double value;

myLabel.text = [NSString stringWithFormat:@"%d\u0025", value ]

u0025 is the unicode character for 'percent sign'

answered Apr 23 '13 at 14:55

Ríomhaire

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score 0 · Answer 5 · answered Apr 23 '13 at 14:58

0

NSInteger percentageProgress = (NSInteger) (Progress * 100);
[lblPercent setText:[NSString stringWithFormat:@"%d%%", percentageProgress]];

answered Apr 23 '13 at 14:58

Mikhail

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score 0 · Answer 6 · answered May 11 '13 at 18:33

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NSString *string = [NSString stringWithFormat:@"%.0f%@",Progress, @"%"];
[lblPercent setStringValue:string];

This seems to had worked for me doing it the way I had done it...

answered May 11 '13 at 18:33

Jonathan Weinraub

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How do I combine a char with an int in an NSTextField in Objective-C?

6 Answers6