omit xml declaration when saving xml with boost

Question

Is it possible, via the xml_writer_settings used as third parameter in the write_xml call, to omit the xml declaration when the function saves the xml? I mean, I would like not to have the initial "xml version="blah" encoding="blah blah" part. I'm searching the internet but I still haven't found an answer. How to do it?

You can just trim the first string containing after write_xml() — AlexT, Feb 04 '14 at 15:40

Stamen Rakov · Answer 1 · 2016-03-31T07:29:57.763

8

Yes, it is possible, but you'll need to call the function 'write_xml_element' directly. Here is an example with boost 1.49:

using namespace boost::property_tree;
ptree pt;
...
write_xml_element(std::cout,ptree::key_type(),pt,-1,xml_writer_settings<ptree::key_type::value_type>());

Of course. you can replace the standard output with std::ofstream or any other output stream you want.

edited Mar 31 '16 at 07:29

answered Mar 30 '16 at 11:14

Stamen Rakov

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Note for anyone who stumbles across this answer: If you want to update this for boost in later versions (I'm on 1.69), just omit `::value_type` in `xml_writer_settings<>` (so it's `xml_writer_settings()`) - newer boost versions use the `key_type` to get the `value_type`. My code is just: `write_xml_element(std::cout, {}, tree, -1, xml_writer_settings{});`. Thanks for your answer, helped me a lot! – oldjohn1994 May 20 '19 at 02:40

ForEveR · Accepted Answer · 2013-04-17T11:19:52.650

1

No, it's not possible. look here for members of xml_writer_settings

And too, write_xml calls write_xml_internal that is (in boost 1.52)

template<class Ptree>
void write_xml_internal(
std::basic_ostream<typename Ptree::key_type::value_type> &stream, 
const Ptree &pt,
const std::string &filename,
const xml_writer_settings<typename Ptree::key_type::value_type> & settings)
{
    typedef typename Ptree::key_type::value_type Ch;
    typedef typename std::basic_string<Ch> Str;
    stream  << detail::widen<Ch>("<?xml version=\"1.0\" encoding=\"")
            << settings.encoding
            << detail::widen<Ch>("\"?>\n");
    write_xml_element(stream, Str(), pt, -1, settings);
    if (!stream)
        BOOST_PROPERTY_TREE_THROW(xml_parser_error("write error", filename, 0));
}

edited Apr 17 '13 at 11:19

answered Apr 17 '13 at 11:07

ForEveR

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What do you mean with "it's not real"? – Magallo Apr 17 '13 at 11:08
@Magallo that it's not possible. – ForEveR Apr 17 '13 at 11:20
ah, not possible. Well, it's very disappointing. I knew boost used rapidxml internally. I know that this is possible with rapidxml, I really don't understand why they did not give us this possibility. Thank you for your answer anyway. – Magallo Apr 17 '13 at 12:54

score 0 · Answer 3 · answered Sep 27 '17 at 06:07

It seems that write_xml_element can't work without xml_writer_settings. And xml_writer_settings has two different incompatible versions; one with and another with .

In boost v1.58 this line is valid:

boost::property_tree::xml_writer_settings<std::string> settings;
boost::property_tree::xml_parser::write_xml_element(xmlStream,ptree::key_type(),pt_,-1, settings);

while in boost 1.54 these are valid:

boost::property_tree::xml_writer_settings<char> settings;
boost::property_tree::xml_parser::write_xml_element(xmlStream,ptree::key_type(),pt_,-1, settings);

I'm not sure if there is any solution for unifying them. So consider the boost version when working with write_xml_element.

omit xml declaration when saving xml with boost

3 Answers3