Using awk and df (disk free) to show only mount name and space used

Question

What would be the correct CL sequence to execute a df -h and only print out the mount name and used space (percentage)? I'm trying to do a scripted report for our servers.

I tried

df -h | awk '{print $1 $4}'

which spits out

$df -h | awk '{print $1 $4}'
FilesystemAvail
/dev/sda164G
udev3.9G
tmpfs1.6G
none5.0M
none3.9G
none100M
/home/richard/.Private64G

How would you change this to add spacing? Am I selecting the right columns?

Hi KingsIndian, I added more information about. Specifically, how would I add spacing in awk? — Rick, Apr 16 '13 at 19:37

score 9 · Accepted Answer · answered Apr 16 '13 at 19:35

9

Try this:

df -h | awk '{if ($1 != "Filesystem") print $1 " " $5}'

Or just

df -h | awk '{print $1 " " $5}'

if you want to keep the headers.

answered Apr 16 '13 at 19:35

Ansgar Wiechers

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score 5 · Answer 2 · answered Apr 16 '13 at 19:36

5

You are almost there:

df -h | awk 'NR>1{print $1, $5}'

answered Apr 16 '13 at 19:36

perreal

94,503
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score 1 · Answer 3 · answered Apr 16 '13 at 19:38

The issues with your code are what input to process, and how to format the output.

As an example, this awk selects records that have a % symbol at the end of field five, and put a space between the two output fields.

 df -h | awk '$5 ~ /\%$/ {print $1 " " $5 }'

Everything else is just refining those two things.

Using awk and df (disk free) to show only mount name and space used

3 Answers3