contains quotation mark java

Question

how to I add an argument to check if a string contains ONE quotation mark ? I tried to escape the character but it doesn't work

words[i].contains()

EDIT: my bad, got some unclosed brackets, works fine now

isn't `words[i].contains("\"")` working ? – PermGenError Apr 16 '13 at 13:07 — PermGenError, Apr 16 '13 at 13:07

score 5 · Answer 1 · answered Apr 16 '13 at 13:13

5

words[i].matches("[^\"]*\"[^\"]*")

That is: any non-quotes, a quote, any non-quotes.

answered Apr 16 '13 at 13:13

Joop Eggen

score 4 · Answer 2 · answered Apr 16 '13 at 13:08

4

You could use something like this:

words[i].split("\"").length - 1

That would give you the amount of "s in your string. Therefore, just use:

if (words[i].split("\"").length == 2) {
    //do stuff
}

answered Apr 16 '13 at 13:08

tckmn

Why split when the requirement is `to contain one` ? – Shark Apr 16 '13 at 13:10
@Shark because `contains` can't tell you how many there are. the OP said exactly one. – tckmn Apr 16 '13 at 13:10
2

why do you use split and not regex? – om-nom-nom Apr 16 '13 at 13:11
@om-nom-nom Again, regex can't tell you how many `"`s there are. The OP said he wanted exactly 1. – tckmn Apr 16 '13 at 13:12
2

No, it **can** say if there is exactly one mark, e.g. something like `[^"]*\"[^"]*` – om-nom-nom Apr 16 '13 at 13:13
1

this is far easier to understand than regex. – Oliver Watkins Apr 16 '13 at 13:17
1

@OliverWatkins yep, but this more likely far less performant too – om-nom-nom Apr 16 '13 at 13:17
1

i would hazard a guess that both approaches would still be under 1 millisecond. What you don't want to do is premature optimization. – Oliver Watkins Apr 16 '13 at 13:26

johnchen902 · Answer 3 · 2013-07-02T13:20:41.913

2

You can check if the first quotation mark exists, and then check if the second one doesn't. ~~It's much faster than using matches or split.~~

int index = words[i].indexOf('\"');
if (index != -1 && words[i].indexOf('\"', index + 1) == -1){
    // do stuff
}

edited Jul 02 '13 at 13:20

answered Apr 16 '13 at 13:24

johnchen902

"much faster?" yeah... about a ten nanosecond gain off 30 nanoseconds or something. You won't ever notice the difference – tckmn Apr 16 '13 at 16:04

score 0 · Answer 4 · answered Apr 16 '13 at 13:28

0

To check number or quotes you can also use length of string after removing ".

int quotesNumber = words[i].length() - words[i].replace("\"", "").length();
if (quotesNumber == 1){
    //do stuff
}

answered Apr 16 '13 at 13:28

Pshemo

4 Answers4