I'm trying:
import commands
print commands.getoutput("ps -u 0")
But it doesn't work on os x. os instead of commands gives the same output: USER PID %CPU %MEM VSZ RSS TT STAT STARTED TIME COMMAND
nothing more
This works on Mac OS X 10.5.5. Note the capital -U option. Perhaps that's been your problem.
import subprocess
ps = subprocess.Popen("ps -U 0", shell=True, stdout=subprocess.PIPE)
print ps.stdout.read()
ps.stdout.close()
ps.wait()
Here's the Python version
Python 2.5.2 (r252:60911, Feb 22 2008, 07:57:53)
[GCC 4.0.1 (Apple Computer, Inc. build 5363)] on darwin
If the OS support the /proc fs you can do:
>>> import os
>>> pids = [int(x) for x in os.listdir('/proc') if x.isdigit()]
>>> pids
[1, 2, 3, 6, 7, 9, 11, 12, 13, 15, ... 9406, 9414, 9428, 9444]
>>>
A cross-platform solution (linux, freebsd, osx, windows) is by using psutil:
>>> import psutil
>>> psutil.pids()
[1, 2, 3, 6, 7, 9, 11, 12, 13, 15, ... 9406, 9414, 9428, 9444]
>>>
The cross-platform replacement for commands
is subprocess
. See the subprocess module documentation. The 'Replacing older modules' section includes how to get output from a command.
Of course, you still have to pass the right arguments to 'ps' for the platform you're on. Python can't help you with that, and though I've seen occasional mention of third-party libraries that try to do this, they usually only work on a few systems (like strictly SysV style, strictly BSD style, or just systems with /proc.)
It works if you use os instead of commands:
import os
print os.system("ps -u 0")