My mistake with "strpos" function? php

Question

I am trying to get strpos to search string variable $string for the phrase "test" and if it doesn't contain "test" another variable $change is redefined as $string2 (where $change has been defined previously)

if (strpos($string, 'test') == false) {
  $change = $string2;
  break;
 }

But unfortunately it doesn't work.

Is there a mistake in the above?

Thank you.

possible duplicate of [Question about strpos in PHP](http://stackoverflow.com/questions/1004897/question-about-strpos-in-php) — , Jul 17 '12 at 03:16

score 6 · Accepted Answer · answered Oct 20 '09 at 01:46

strpos returns false if it does not find the string, which is equivalent to 0 in a type-unspecific conditional in PHP. Make sure to use the === operator when comparing using strpos.

if (strpos($string, 'test') === false) {
  $change = $string2;
  break;
}

score 3 · Answer 2 · answered Oct 20 '09 at 01:49

3

Try using

if (strpos($string, 'test') === false)

=== instead of ==

answered Oct 20 '09 at 01:49

Shankar R10N

4,926
1
21
24

score 3 · Answer 3 · answered Oct 20 '09 at 01:54

strpos can return "false" or can return "0" which can be misread as false, so instead of using the == comparison operator (which means "equal to") you have to use === (which means identical to). You might also consider a ternary statement instead of a break:

  $change = (strpos($string, 'test') === false) ? $string2 : $change;

My mistake with "strpos" function? php

3 Answers3