Assign object the return value of boost::lambda::bind?

Question

I would think it could be useful to store a bound lambda function to be used later, yet I haven't seen any examples on the return value of the boost::lambda::bind function being assigned to an object of that return type. Is there no way to do this cleanly, or is there just no reason to do it?

Example:

boost::lambda::lambda_functor<?> lf = boost::lambda::bind(boost::lambda::constructor<Foo>(), x);

I am not familiar with Boost.Lambda, but in C++11, you can use `auto` — Andy Prowl, Apr 04 '13 at 17:42
If you're already using C++11, there isn't a great need for boost::lambda; lambdas are already part of the language in C++11. — Salami, May 30 '14 at 03:14

score 4 · Accepted Answer · answered Apr 04 '13 at 17:46

4

Use boost.Function to store function objects:

boost::function<Foo()> lf = boost::lambda::bind(boost::lambda::constructor<Foo>(), x);

answered Apr 04 '13 at 17:46

kassak

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Assign object the return value of boost::lambda::bind?

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