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I'm trying to create instance of an object that also have classes composed in to it:

[DataContract(Name = "share", Namespace = "")]
public class RequestShareDocument
{
    [DataMember(Order = 0)]
    public string profile_name { get; set; }
    [DataMember(Order = 1)]
    public List<RequestSigner> signers {get; set;}
    [DataMember(Order = 2)]
    public bool createcopy { get; set; }
}

[DataContract(Name = "signer", Namespace = "")]
public class RequestSigner
{
    [DataMember(Order = 0)]
    public string email { get; set; }
    [DataMember(Order = 1)]
    public string order { get; set; }
    [DataMember(Order = 2)]
    public string reminder { get; set; }
    [DataMember(Order = 3)]
    public RequestSignerPermissions permissions { get; set; }
    [DataMember(Order = 4)]
    public string signature_field { get; set; }
}

[DataContract(Name = "permissions", Namespace = "")]
public class RequestSignerPermissions
{
    [DataMember(Order = 0)]
    public bool save_locally {get;set;}
    [DataMember(Order = 1)]
    public string open_password { get; set; }
    [DataMember(Order = 2)]
    public DateTime accessible_after { get; set; }
    [DataMember(Order = 3)]
    public DateTime accessible_before { get; set; }
    [DataMember(Order = 4)]
    public string certify_level { get; set; }
}

I need to create an instance of class and serialize in to XML, but I don't know how to do this?

I'm able to create an instance of a class but when it comes to the List<T> property I'm not able to create it. I've already tried this:

if (typeof(IEnumerable).IsAssignableFrom(item.PropertyType))
    IList list = (IList)Activator.CreateInstance(typeof(List<>));

...and to serialize I'm using:

XmlSerializer mySerializer = new XmlSerializer(typeof(T), new
    XmlRootAttribute(RootElementName));       
StringWriter sww = new StringWriter();
XmlWriter writer = XmlWriter.Create(sww, new XmlWriterSettings()
    { OmitXmlDeclaration = true, Indent = true });
mySerializer.Serialize(writer, item);
writer.Close();
sww.Close();

Problem is when I loop all properties and reach the List I don't know how to create an instance of List. Is it possible or am I doing something wrong?

Daniel A.A. Pelsmaeker
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Salman
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  • Did you try this: `if ( typeof(IList).IsAssignableFrom(item.PropertyType)) { IList list = (IList)Activator.CreateInstance(item.PropertyType);` – Vyacheslav Volkov Apr 03 '13 at 15:28
  • i have tired it already it creates an instance of list but problem is how i can add object of class whose list is created . IList list = (IList)Activator.CreateInstance(item.PropertyType); now i get list object with count of 0 – Salman Apr 04 '13 at 06:18

1 Answers1

1

If I have understood correctly, this code does what you want:

public static object InitializeTarget(Type type)
    {
        object target = CreateObject(type);
        foreach (PropertyInfo propertyInfo in type.GetProperties())
        {
            if (propertyInfo.PropertyType.IsClass && propertyInfo.CanWrite
                && propertyInfo.PropertyType != typeof(string)
                && (propertyInfo.IsDefined(typeof(DataMemberAttribute), true)))
                propertyInfo.SetValue(target, InitializeTarget(propertyInfo.PropertyType), null);
        }
        return target;
    }

    public static object CreateObject(Type type)
    {
        if (typeof(IList).IsAssignableFrom(type) && type.IsGenericType)
        {
            Type[] genericArguments = type.GetGenericArguments();
            if (genericArguments.Length == 1)
            {
                var list = (IList)Activator.CreateInstance(type);
                //Adding default value
                list.Add(CreateObject(genericArguments[0]));
                return list;
            }
        }
        //If the object is only to serialize, you can use it
        return FormatterServices.GetUninitializedObject(type);
        //or
        //            return Activator.CreateInstance(type);
    }
Vyacheslav Volkov
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