C++/Boost split a string on more than one character

Question

This is probably really simple once I see an example, but how do I generalize boost::tokenizer or boost::split to deal with separators consisting of more than one character?

For example, with "__", neither of these standard splitting solutions seems to work :

boost::tokenizer<boost::escaped_list_separator<string> > 
        tk(myString, boost::escaped_list_separator<string>("", "____", "\""));
std::vector<string> result;
for (string tmpString : tk) {
    result.push_back(tmpString);
}

or

boost::split(result, myString, "___");

Please be specific about what "does not seem to work" means. — Drew Dormann, Apr 03 '13 at 14:02
possible duplicate of [Boost::Split using whole string as delimiter](http://stackoverflow.com/questions/7436968/boostsplit-using-whole-string-as-delimiter) — jogojapan, Apr 03 '13 at 14:05

score 10 · Accepted Answer · answered Apr 03 '13 at 14:02

10

boost::algorithm::split_regex( result, myString, regex( "___" ) ) ;

answered Apr 03 '13 at 14:02

Can you please let me know that are the header files to be included to do this? – Kadiam Sep 08 '16 at 13:16
2

@Kadiam Try: #include – Chrille Aug 17 '17 at 09:28

score 1 · Answer 2 · answered Apr 03 '13 at 14:03

1

you have to use splitregex instead: http://www.daniweb.com/software-development/cpp/threads/118708/boostalgorithmsplit-with-string-delimeters

answered Apr 03 '13 at 14:03

Penfold

599
4
8

score 1 · Answer 3 · answered Jul 17 '19 at 23:12

Non-boost solution

vector<string> split(const string &s, const string &delim){
    vector<string> result;
    int start = 0;
    int end = 0;
    while(end!=string::npos){
        end = s.find(delim, start);
        result.push_back(s.substr(start, end-start));
        start = end + delim.length();
    }
    return result;
}

C++/Boost split a string on more than one character

3 Answers3

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